∫(7x^3-6x+8)dx/(x^2+1)
=∫[7x-13x/(x^2+1)+8/(x^2+1)]dx
=(7/2)x^2-(13/2)ln(x^2+1)+8arctanx+c.
0
∫(7x^3-6x+8)dx/(x^2+1)
=∫[7x-13x/(x^2+1)+8/(x^2+1)]dx
=(7/2)x^2-(13/2)ln(x^2+1)+8arctanx+c.